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x^2-109x+1290=0
a = 1; b = -109; c = +1290;
Δ = b2-4ac
Δ = -1092-4·1·1290
Δ = 6721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-109)-\sqrt{6721}}{2*1}=\frac{109-\sqrt{6721}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-109)+\sqrt{6721}}{2*1}=\frac{109+\sqrt{6721}}{2} $
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